(y+3)(4y^2-3y-3)=

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Solution for (y+3)(4y^2-3y-3)= equation: 


Simplifying
(y + 3)(4y2 + -3y + -3) = 0

Reorder the terms:
(3 + y)(4y2 + -3y + -3) = 0

Reorder the terms:
(3 + y)(-3 + -3y + 4y2) = 0

Multiply (3 + y) * (-3 + -3y + 4y2)
(3(-3 + -3y + 4y2) + y(-3 + -3y + 4y2)) = 0
((-3 * 3 + -3y * 3 + 4y2 * 3) + y(-3 + -3y + 4y2)) = 0
((-9 + -9y + 12y2) + y(-3 + -3y + 4y2)) = 0
(-9 + -9y + 12y2 + (-3 * y + -3y * y + 4y2 * y)) = 0
(-9 + -9y + 12y2 + (-3y + -3y2 + 4y3)) = 0

Reorder the terms:
(-9 + -9y + -3y + 12y2 + -3y2 + 4y3) = 0

Combine like terms: -9y + -3y = -12y
(-9 + -12y + 12y2 + -3y2 + 4y3) = 0

Combine like terms: 12y2 + -3y2 = 9y2
(-9 + -12y + 9y2 + 4y3) = 0

Solving
-9 + -12y + 9y2 + 4y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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